PERT Practice Test 2026 – Complete Guide for Exam Prep

Question: 1 / 400

Which of the following values satisfies the equation x^2 - 6x + 5 = 0?

x=5

To determine which value satisfies the equation \(x^2 - 6x + 5 = 0\), it helps to factor the quadratic expression. The equation can be factored into \((x - 1)(x - 5) = 0\). This reveals two possible solutions for \(x\): \(x = 1\) and \(x = 5\).

When we test the value of \(x = 5\) in the original equation:

1. Substitute \(x = 5\) into the equation:

\[

(5)^2 - 6(5) + 5 = 25 - 30 + 5 = 0.

\]

Since substituting \(x = 5\) results in the left-hand side equalling zero, it confirms that \(x = 5\) is indeed a solution to the equation.

In contrast, \(x = 1\) also satisfies the equation since performing the same substitution would give:

\[

(1)^2 - 6(1) + 5 = 1 - 6 + 5 = 0,

\]

so this value is also a correct solution.

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x=1

x=4

x=0

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