PERT Practice Test 2026 – Complete Guide for Exam Prep

Question: 1 / 400

What is the product of (2k^2 - 6k + 9)(k + 3)?

2k^3 - 9k + 27

To find the product of the two polynomials \( (2k^2 - 6k + 9)(k + 3) \), you can apply the distributive property, also known as the FOIL method for binomials, which involves multiplying each term in the first polynomial by each term in the second polynomial.

1. Start by distributing \( k \):

- \( 2k^2 \cdot k = 2k^3 \)

- \( -6k \cdot k = -6k^2 \)

- \( 9 \cdot k = 9k \)

After adding these terms together, we get:

\( 2k^3 - 6k^2 + 9k \)

2. Next, distribute \( 3 \):

- \( 2k^2 \cdot 3 = 6k^2 \)

- \( -6k \cdot 3 = -18k \)

- \( 9 \cdot 3 = 27 \)

After adding these terms together, we get:

\( 6k^2 - 18k + 27 \)

3. Now

Get further explanation with Examzify DeepDiveBeta

2k^3 - 12k + 27

2k^3 - 6k + 27

2k^3 + 6k + 27

Next Question

Report this question

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy